jika EF = FG dan EG memiliki panjang 625 cm,maka tentukan panjang EF !!
Teorema Pythagoras
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[tex]\begin{gathered}\begin{aligned} \sf s \sqrt{2} &=\sf d\\ \sf s \sqrt{2} &= \sf 625 \\ \sf s&= \sf \frac{625}{ \sqrt{2} } \\ \sf s&= \sf \frac{625}{ \sqrt{2}} \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \sf s &= \frac{625 \sqrt{2} }{2} \end{aligned}\end{gathered}[/tex]
[tex] \: [/tex]
